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IConstructLine.ConstructAngleBisector Method (ArcObjects .NET 10.6 SDK)
ArcObjects Library Reference (Geometry)  

IConstructLine.ConstructAngleBisector Method

Constructs a line segment being the bisector through the angle defined by the three input points.

[Visual Basic .NET]
Public Sub ConstructAngleBisector ( _
    ByVal from As IPoint, _
    ByVal through As IPoint, _
    ByVal to As IPoint, _
    ByVal Length As Double, _
    ByVal useAcuteAngle As Boolean _
)

[C#]
public void ConstructAngleBisector (
    IPoint from,
    IPoint through,
    IPoint to,
    double Length,
    bool useAcuteAngle
);

[C++]
HRESULT ConstructAngleBisector(
  IPoint* from,
  IPoint* through,
  IPoint* to,
  double Length,
  VARIANT_BOOL useAcuteAngle
);

[C++]

Parameters
from 

  from is a parameter of type IPoint*
through 

  through is a parameter of type IPoint*
to 

  to is a parameter of type IPoint*
Length 

  Length is a parameter of type double
useAcuteAngle 

  useAcuteAngle is a parameter of type bool

Product Availability

Available with ArcGIS Engine, ArcGIS Desktop, and ArcGIS Server.

Description

Constructs a Line segment of given input Length which bisects the Angle formed by the right side of the three input points.  The From Point of the new Line is the Through input point.  If the right side angle is smaller, the constructed Line will always bisect this angle, regardless of the value of bUseSmallerAngle.  However, if the right side angle is larger, and bUseSmallerAngle is TRUE, then the constructed line will bisect the smaller angle (left side) instead of the right side reflex angle.

Remarks

 

ConstructLine ConstructAngleBisector Example

[C#]

// This example constructs a new line using the ConstructAngleBisector method.
// Note the usage of the acute angle.
public void ConstructLineFromAngleBisector()
{
    IPoint fromPoint=new PointClass();
    fromPoint.PutCoords(1, 0);
    IPoint throughPoint=new PointClass();
    throughPoint.PutCoords(1, 1);
    IPoint toPoint=new PointClass();
    toPoint.PutCoords(0, 1);

    IConstructLine constructLine=new LineClass();

    double distance=1.4142135623731;
    constructLine.ConstructAngleBisector(fromPoint, throughPoint, toPoint, distance, false);
    ILine line=constructLine as ILine;

    printProperties(line);
    // Now use the the acute angle with the same data.
    //Gives same results as setting dDist to -1.4142135623731 and not using
    // the acute angle.
    constructLine.ConstructAngleBisector(fromPoint, throughPoint, toPoint, distance, true);
    ILine line2=constructLine as ILine;
    printProperties(line2);
}
private void printProperties(ILine line)
{
    IPoint outFromPoint=new PointClass();
    IPoint outToPoint=new PointClass();
    line.QueryCoords(outFromPoint, outToPoint);
    System.Windows.Forms.MessageBox.Show(outFromPoint.X + " , " +
                                   outFromPoint.Y + " , " +
                                   outToPoint.X + " , " +
                                   outToPoint.Y + "\n" +
                                   "angle=" + line.Angle);
}

[Visual Basic .NET]

    '+++ This example constructs a new line using the ConstructAngleBisector method.
    '+++ Note the usage of the acute angle.

    Public Sub t_Line_ConstructAngleBisector()
        On Error GoTo Errorhandler
        Dim pPointFrom As IPoint
        Dim pPointTo As IPoint
        Dim pPointThrough As IPoint
        Dim pLine As ILine
        Dim pCLine As IConstructLine
        Dim dDist As Double
        Dim pP1 As IPoint
        Dim pP2 As IPoint

        pPointFrom=New Point
        pPointTo=New Point
        pPointThrough=New Point
        pLine=New Line
        pCLine=New Line
        pP1=New Point
        pP2=New Point

        pPointFrom.PutCoords(1, 0)
        pPointTo.PutCoords(0, 1)
        pPointThrough.PutCoords(1, 1)
        dDist=1.4142135623731

        pCLine.ConstructAngleBisector(pPointFrom, pPointThrough, pPointTo, dDist, False)
        pLine=pCLine
        pLine.QueryCoords(pP1, pP2)
        MsgBox(pP1.X & "," & pP1.Y & " to " & pP2.X & "," & pP2.Y _
        & vbCrLf & "angle=" & pLine.Angle)


        '+++ Now use the the acute angle with the same data.
        '+++ Gives same results as setting dDist to -1.4142135623731 and not using
        '+++ the acute angle.

        pCLine.ConstructAngleBisector(pPointFrom, pPointThrough, pPointTo, dDist, True)
        pLine=pCLine
        pLine.QueryCoords(pP1, pP2)
        MsgBox(pP1.X & "," & pP1.Y & " to " & pP2.X & "," & pP2.Y _
        & vbCrLf & "angle=" & pLine.Angle)

        Exit Sub

Errorhandler:
        MsgBox(Err.Number & "..." & Err.Description)
        Exit Sub

    End Sub

See Also

IConstructLine Interface