ST_Within

定义

如果第一个 ST_Geometry 对象完全位于第二个 ST_Geometry 对象的范围内，则 ST_Within 返回 1（Oracle 和 SQLite）或 t (PostgreSQL)；否则，返回 0（Oracle 和 SQLite）或 f (PostgreSQL)。

语法

Oracle 和 PostgreSQL

sde.st_within (geometry1 sde.st_geometry, geometry2 sde.st_geometry)

SQLite

st_within (geometry1 geometryblob, geometry2 geometryblob)

返回类型

布尔型

示例

下例中，创建了两个表文件：zones 和 squares。SELECT 语句将找出相交但不完全处于同一地块内的所有正方形。

Oracle

CREATE TABLE squares (
 id integer,
 shape sde.st_geometry);

CREATE TABLE zones (
 id integer,
 shape sde.st_geometry);


INSERT INTO squares (id, shape) VALUES (
 1,
 sde.st_polygon ('polygon ((0 0, 0 10, 10 10, 10 0, 0 0))', 4326)
);

INSERT INTO squares (id, shape) VALUES (
 2,
 sde.st_polygon ('polygon ((20 0, 20 10, 30 10, 30 0, 20 0))', 4326)
);

INSERT INTO squares (id, shape) VALUES (
 3,
 sde.st_polygon ('polygon ((40 0, 40 10, 50 10, 50 0, 40 0))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 1,
 sde.st_polygon ('polygon ((-1 -1, -1 11, 11 11, 11 -1, -1 -1))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 2,
 sde.st_polygon ('polygon ((19 -1, 19 11, 29 9, 31 -1, 19 -1))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 3,
 sde.st_polygon ('polygon ((39 -1, 39 11, 51 11, 51 -1, 39 -1))', 4326)
);

SELECT s.id sq_id
 FROM SQUARES s, ZONES z
 WHERE sde.st_intersects (s.shape, z.shape) = 1 
 AND sde.st_within (s.shape, z.shape) = 0;

SQ_ID

2

PostgreSQL

CREATE TABLE squares (
 id integer,
 shape sde.st_geometry);

CREATE TABLE zones (
 id integer,
 shape sde.st_geometry);


INSERT INTO squares (id, shape) VALUES (
 1,
 sde.st_polygon ('polygon ((0 0, 0 10, 10 10, 10 0, 0 0))', 4326)
);

INSERT INTO squares (id, shape) VALUES (
 2,
 sde.st_polygon ('polygon ((20 0, 20 10, 30 10, 30 0, 20 0))', 4326)
);

INSERT INTO squares (id, shape) VALUES (
 3,
 sde.st_polygon ('polygon ((40 0, 40 10, 50 10, 50 0, 40 0))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 1,
 sde.st_polygon ('polygon ((-1 -1, -1 11, 11 11, 11 -1, -1 -1))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 2,
 sde.st_polygon ('polygon ((19 -1, 19 11, 29 9, 31 -1, 19 -1))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 3,
 sde.st_polygon ('polygon ((39 -1, 39 11, 51 11, 51 -1, 39 -1))', 4326)
);

SELECT s.id
 AS sq_id
 FROM squares s, zones z
 WHERE st_intersects (s.shape, z.shape) = 't' 
 AND st_within (s.shape, z.shape) = 'f';

sq_id

2

SQLite

CREATE TABLE squares (
 id integer
);

SELECT AddGeometryColumn(
 NULL,
 'squares',
 'shape',
 4326,
 'polygon',
 'xy',
 'null'
);

CREATE TABLE zones (
 id integer
);

SELECT AddGeometryColumn(
 NULL,
 'zones',
 'shape',
 4326,
 'polygon',
 'xy',
 'null'
);

INSERT INTO squares (id, shape) VALUES (
 1,
 st_polygon ('polygon ((0 0, 0 10, 10 10, 10 0, 0 0))', 4326)
);

INSERT INTO squares (id, shape) VALUES (
 2,
 st_polygon ('polygon ((20 0, 20 10, 30 10, 30 0, 20 0))', 4326)
);

INSERT INTO squares (id, shape) VALUES (
 3,
 st_polygon ('polygon ((40 0, 40 10, 50 10, 50 0, 40 0))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 1,
 st_polygon ('polygon ((-1 -1, -1 11, 11 11, 11 -1, -1 -1))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 2,
 st_polygon ('polygon ((19 -1, 19 11, 29 9, 31 -1, 19 -1))', 4326)
);

INSERT INTO zones (id, shape) VALUES (
 3,
 st_polygon ('polygon ((39 -1, 39 11, 51 11, 51 -1, 39 -1))', 4326)
);

SELECT s.id
 AS "sq_id"
 FROM squares s, zones1 z
 WHERE st_intersects (s.shape, z.shape) = 1 
 AND st_within (s.shape, z.shape) = 0;

sq_id

2